Cs50 Tideman Solution [ PROVEN ◉ ]

# Return the winner if len(candidates) == 1: return candidates[0] else: return None

// Update vote counts for (int i = 0; i < num_candidates; i++) { candidates[i].votes = 0; } for (int i = 0; i < num_voters; i++) { for (int j = 0; j < num_candidates; j++) { if (strcmp(voters[i].preferences[j], "") != 0) { for (int k = 0; k < num_candidates; k++) { if (strcmp(candidates[k].name, voters[i].preferences[j]) == 0) { candidates[k].votes++; } } break; } } } Cs50 Tideman Solution

# Update preferences pairs = update_preferences(pairs, eliminated_candidate) # Return the winner if len(candidates) == 1: